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Question
Assuming that the charges of an electron is 1.6 × 10-19 coulombs, the number of electrons passing through a section of wire per sec, when the wire carries a current of one ampere is:
Options
0.625 × 1019
1.6 × 10-19
1.6 × 1019
0.627 × 10-17
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Solution
0.625 × 1019
Explanation:
Charge = q = e = 1.6 × 10-19 C
Number of electrons = n = ?
Electric current = I = 1A
Time = t = 1S
I = `"q"/"t" = "ne"/"t"`
I = `(1.6xx10^-19xx"n")/1`
`=> "n" = 1/(1.6xx10^-19)`
= 0.625 × 1019
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