Question

Assertion (A): 4ⁿ ends with the digit 0 for some natural number n.

Reason (R): For a number ‘x’ having 2 and 5 as its prime factors, xⁿ always ends with the digit 0 for every natural number n.

Options

• Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).

• Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).

• Assertion (A) is true, but Reason (R) is false.

• Assertion (A) is false, but Reason (R) is true.

Answer 1

Assertion (A) is false, but Reason (R) is true.

Explanation:

A number ends in 0 only when it is divisible by 10, which means it must have both 2 and 5 as prime factors. However, 4ⁿ contains only the factor 2 and no factor 5. Therefore, 4ⁿ cannot end with the digit 0 for any natural number n.