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Assertion: 3/√6 + √3 = √6 − √3 Reason: The rationalising factor of √6 + √3 is √6 − √3. - Mathematics

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Question

Assertion: `3/(sqrt(6) + sqrt(3)) = sqrt(6) - sqrt(3)`

Reason: The rationalising factor of `sqrt(6) + sqrt(3)` is `sqrt(6) - sqrt(3)`.

Options

  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).

  • Assertion (A) is true but Reason (R) is false.

  • Assertion (A) is false but Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

Explanation:

Let’s analyse the assertion and reason:

Assertion: 

To verify this assertion, multiply the numerator and denominator by the conjugate of the denominator:

`3/(sqrt(6) + sqrt(3)) xx (sqrt(6) - sqrt(3))/(sqrt(6) - sqrt(3))`

= `(3(sqrt(6) - sqrt(3)))/(sqrt(6)^2 - (sqrt(3))^2`

= `(3(sqrt(6) - sqrt(3)))/(6 - 3)`

= `(3(sqrt(6) - sqrt(3)))/3`

= `sqrt(6) - sqrt(3)`

Thus, the assertion is true.

Reason:

By definition, the rationalising factor of an expression (a + b) with square roots is its conjugate (a – b), used to eliminate the surds in the denominator by multiplying the numerator and denominator by this conjugate.

Here, the rationalising factor of `sqrt(6) + sqrt(3)` is indeed `sqrt(6) - sqrt(3)`, so the reason is correct.

Since both assertion and reason are true and reason correctly explains the assertion.

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Chapter 1: Rational and Irrational Numbers - Exercise 1F [Page 34]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 1 Rational and Irrational Numbers
Exercise 1F | Q 2. | Page 34
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