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Question
Arrange the following rational numbers in ascending order.
`(10)/(9),(13)/(12) and (19)/(18)`
Sum
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Solution
Given number : `(10)/(9),(13)/(12) and (19)/(18)`
The L.C.M. of 9, 12 and 18 is 36.
Thus, number are:
`(10)/(9)`
= `(10 xx 4)/(9 xx 4)`
= `(40)/(36)`;
`(13)/(12)`
= `(13 xx 3)/(12 xx 3)`
= `(39)/(36)`
and `(19)/(18)`
= `(19 xx 2)/(18 xx 2)`
= `(38)/(36)`.
Since 38 < 39 < 40, we have `(19)/(18) < (13)/(12) < (10)/(9)`.
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