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Question
Arrange the following in decreasing order of their boiling points.
(A) n-butane
(B) 2-methylbutane
(C) n-pentane
(D) 2, 2-dimethylpropane
Options
A > B > C > D
B > C > D > A
D > C > B > A
C > B > D > A
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Solution
C > B > D > A
Explanation:
As the number of carbon atom increases, boiling point increases. Boiling point decreases with branching.
2, 2-dimethyl propane
\[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{H3C - C - CH3}\\
\phantom{}|\\
\phantom{...}\ce{\underset{b.pt = 282.5 K}{CH3}}
\end{array}\]
n-pentane
\[\ce{\underset{b.pt = 309.1 K}{H3C - CH2 - CH2 - CH2 - CH3}}\]
2-methyl butane
\[\begin{array}{cc}
\ce{H3C - H2C - HC - CH3}\\
\phantom{.........}|\\
\phantom{............}\ce{\underset{b.pt = 301 K}{CH3}}
\end{array}\]
n-butane
\[\ce{\underset{(4 carbon atoms with no branching)}{\underset{b.pt = 273 K}{H3C - H2C - CH2 - CH3}}}\]
