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Question
Answer the following:
Show that, logy x3 . logz y4 . logx z5 = 60
Sum
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Solution
L.H.S. = logy (x3) logz (y4) logx (z5)
= (3 logy x) (4 logz y) (5 logx z)
= `60 ((logx)/(logy)) ((logy)/(logz)) ((logz)/(logx))`
= 60
= R.H.S.
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Chapter 6: Functions - Miscellaneous Exercise 6.2 [Page 131]
