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Question
Answer the following question.
Describe any two characteristic features which distinguish between interference and diffraction phenomena. Derive the expression for the intensity at a point of the interference pattern in Young's double-slit experiment.
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Solution
Difference between interference and diffraction:
In the interference pattern, the intensity of the dark fringe is completely zero.
In the diffraction pattern, the intensity of secondary minima is minimum, but not completely zero.
In interference pattern the width of all the interference fringes is equal. In diffraction pattern the width of central maxima is large, and on increasing distance, the width of maxima decreases.
In interference pattern the intensity of all the bright bands is equal.
In the diffraction pattern, the intensity of all the secondary maxima is not equal.
The principle of superposition of light waves:
When two or more wave trains of light travelling in a medium superpose upon each other, the resultant displacement at any instant is equal to the vector sum of the displacements due to individual waves.
If `vecy_1,vecy_2,vecy_3,....` be the displacements due to different waves, then the resultant displacement is given by, `vecy = vecy_1 + vecy_2 + vecy_3 +` ... conditions for constructive and destructive interference:

Let the displacement of the waves from the source `S_1` and `S_2` at a point P on the screen at any time 't' be given by,
`"y"_1 = a_1 sin omegat`
and
`"y"_2 = a_2 sin(omegat + phi)`
where `phi` is the constant phase difference between the two waves
by the superposition principal , the resultant displacement at point P is given by,
`"y" = "y"_1 + "y"_2`
= `a_1 sin omegat + a_2 sin (omegat + phi)`
= `a_1 sin omegat + a_2 sin omegat cos phi + a_2 cos omegat sin phi`
`y = (a_1 + a_2 cos phi) sin omegat + a_2 sin phi cos omegat` ...(i)
Let `a_1 + a_2 cos phi = A cos theta` ...(ii)
`a_2 sin phi = A sin theta` ...(iii)
Then, equation (i) becomes
`"y" = Acostheta sin omegat + A sin theta cos omegat`
`"y" = Asin(omegat + theta)`
Squaring and adding both sides of the equations (ii) and (iii), we obtain
`A^2 cos^2theta + A^2 sin^2 theta = (a_1 + a_2 cos phi)^2 + a_2^2 sin^2 phi`
`A^2 = a_1^2 + a_2^2 (cos^2phi + sin^2phi) + 2a_1a_2 cos phi`
`A^2 = a_1^2 + a_2^2 + 2a_1a_2 cos phi`
The intensity of light is directly proportional to the square of the amplitude of the wave. The intensity of light at point P on the screen is given by,
`I = a_1^2 + a_2^2 + 2a_1a_2 cos phi` ...(iv)
RELATED QUESTIONS
Answer in brief:
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Two coherent sources whose intensity ratio is 25:1 produce interference fringes. Calculate the ratio of amplitudes of light waves coming from them.
In a Young’s double-slit experiment, the slit separation is doubled. To maintain the same fringe spacing on the screen, the screen-to-slit distance D must be changed to ______.
How does wavefront division provide coherent sources?
In Young’s double-slit experiment, 62 fringes are seen in the visible region for sodium light of wavelength 5893 Å. If violet light of wavelength 4359 Å is used in place of sodium light, then what is the number of fringes seen?
In a Young's double-slit experiment, the intensity at a point where the path difference is `lambda/3` (`lambda` being the wavelength of the light used) is I. If I0 denotes the maximum intensity, then `"I"/"I"_0` is equal to ______.
In Young's experiment, the distance between the slits is doubled and the distance between the slit and screen is reduced to half, then the fringe width ____________.
In the biprism experiment, a source of monochromatic light is used for a certain distance between slit and eyepiece. When the distance between two virtual sources is changed from dA to dB, then the fringe width is changed from ZA to ZB. The ratio ZA to ZB is ______
In Young's double-slit experiment, the distance between the slits is 3 mm and the slits are 2 m away from the screen. Two interference patterns can be obtained on the screen due to light of wavelength 480 nm and 600 run respectively. The separation on the screen between the 5th order bright fringes on the two interference patterns is ______
In biprism experiment, the distance of 20th bright band from the central bright band is 1.2 cm. Without changing the experimental set-up, the distance of 30th bright band from the central bright band will be ______.
