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Question
Answer the following.
How are XeO3 and XeOF4 prepared?
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Solution
1) Preparation of XeO3:
Fluorides of xenon react with water to form XeO3.
i) \[\ce{\underset{\text{Xenon tetrfluoride}}{3XeF4} + \underset{\text{Water}}{6H2O} -> \underset{\text{Xenon}}{2Xe} + \underset{\text{Xenon trioxide}}{XeO3} + 12HF + 1 \frac{1}{2} O2}\]
ii) \[\ce{\underset{\text{Xenon hexafluoride}}{XeF6} + \underset{\text{Water}}{3H2O} -> \underset{\text{Xenon trioxide}}{XeO3} + 6HF}\]
2) Preparation of XeOF4:
Partial hydrolysis of XeF6 yields XeOF4.
\[\ce{\underset{\text{Xenon hexafluoride}}{XeF6} + \underset{\text{Water}}{H2O} -> \underset{\text{Xenon monooxytetrafluoride}}{XeOF4} + \underset{\text{Hydrogen fluoride}}{2HF}}\]
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