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An observer can see through a small hole on the side of a jar (radius 15 cm) at a point at a height of 15 cm from the bottom (see figure). The hole is at a height of 45 cm. - Physics (Theory)

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Question

An observer can see through a small hole on the side of a jar (radius 15 cm) at a point at a height of 15 cm from the bottom (see figure). The hole is at a height of 45 cm. When the jar is filled with a liquid up to a height of 30 cm, the same observer can see the edge at the bottom of the jar. If the refractive index of the liquid is `N/100`, where N is an integer, the value of N is ..........

Numerical
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Solution

From the figure,

sin i = `15/(15 sqrt2) = 1/sqrt2`

and sin r = `15/sqrt(15^2 + 30^2)`

= `1/sqrt5`

n = `sin i/sin r`

= `sqrt(5/2)`

= 1.58

= `158/100`

Thus, N = 158.

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Chapter 15: Refraction of Light at a Plane Interface : Total Internal Reflection : Optical Fibre - For Different Competitive Examinations [Page 788]

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Nootan Physics Part 1 and 2 [English] Class 12 ISC
Chapter 15 Refraction of Light at a Plane Interface : Total Internal Reflection : Optical Fibre
For Different Competitive Examinations | Q 1. | Page 788
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