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Question
An isotope of hydrogen (A) reacts with diatomic molecule of element which occupies group number 16 and period number 2 to give compound (B) is used as a moderator in nuclear reaction. (A) adds on to a compound (C), which has the molecular formula C3H6 to give (D). Identify A, B, C and D.
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Solution
An isotope of hydrogen (A) reacts with diatomic molecule of element which occupies group number 16 and period number 2 to give compound (B) is used as a moderator in nuclear reaction.
\[\ce{2D2 + O2 -> 2D2O}\]
The isotope of hydrogen is deuterium (A), diatomic element is oxygen and the compound (B) is heavy water.
(A) adds on to a compound (C), which has the molecular formula C3H6 to give (D).
\[\ce{\underset{\text{(C)}}{CH3} - CH = CH2 + D2 -> \underset{\text{(D)}}{CH3} - CHD - CH2D}\]
The compound (C) is propene and (D) is 1, 2 deutropropane.
- A – Deuterium (D2)
- B – Heavy water (D2O)
- C – Propene \[\ce{(CH3 - CH = CH2)}\]
- D – 1, 2 deutero propene \[\ce{(CH3 - CHD - CH2D)}\]
