Question

An imaginary radioactive element `"_92X^235` decays to form X₁; X₂; X₃; X₄; X₅ and X₆ nuclides, by ejecting two β-particles, followed by α-particles and again two β-particles, followed by α-particle. Represent the various nuclear changes in the form of an equation. State the mass number and atomic number of X₆. List the isotopes and isobars in the above nuclear equation.

Answer 1

\[\ce{_92X^235->[-β]_93X1^235->[-β]_94X2^235->[-α]_92X3^231->[-β]_93X4^231->[-β]_94X5^231->[-α]_92X6^227}\]

The mass number and atomic number of X₆ is 227 and 92 respectively.

Isotopes (a) \[\ce{_92X^234, _92X3^231, _92X6^227}\]
(b) \[\ce{_93X1^235;_93X4^231}\]
(c) \[\ce{_94X2^235;_94X5^231}\]

Isobars (a) \[\ce{_92X^235; _93X1^235;_94X2^235}\]

(b) \[\ce{_92X3^231; _93X4^231; _94X5^231}\]