Question

An advertising executive is studying television viewing habits of married men and women during prime time hours. Based on the past viewing records he has determined that during prime time wives are watching television 60% of the time. It has also been determined that when the wife is watching television, 40% of the time the husband is also watching. When the wife is not watching the television, 30% of the time the husband is watching the television. Find the probability that if the husband is watching the television, the wife is also watching the television

Answer 1

P(Wife watchhing TV) = {(W) = `60/100`

P(H/W) = `40/100`; P(H/W') = `30/100`

P(W/H) = `("P"("H"/"W")"P"("W"))/("P"("H"))`

= `(40/100 xx  60/100)/(9/25)`

= `24/100 xx 9/25`

= `24/100 xx 25/9`

= `24/(4 xx 9)`

= `24/36`

= `2/3`