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Among equimolal solutions of MgCl2, NaCl, FeCl3 and C12H22O11, which will show minimum osmotic pressure? Why? - Chemistry (Theory)

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Question

Among equimolal solutions of MgCl2, NaCl, FeCl3 and C12H22O11, which will show minimum osmotic pressure? Why?

Short Answer
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Solution

C12H22O11

Explanation:

Osmotic pressure is given by 

π = i CRT 

In this equation, i represents the van’t Hoff factor, which indicates the number of particles produced by a solute in solution.

C12H22O11 (sucrose) is a non-electrolyte, so i is 1.

NaCl → i = 2, MgCl2 → i = 3, FeCl3 → i = 4

Since sucrose produces the fewest particles, it has the lowest osmotic pressure among equimolal solutions.

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Chapter 2: Solutions - QUESTIONS FROM ISC EXAMINATION PAPERS [Page 130]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 2 Solutions
QUESTIONS FROM ISC EXAMINATION PAPERS | Q 12. (b) | Page 130
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