Question

Aluminium carbide reacts with water according to the following equation.

\[\ce{Al4C3 + 12H2O -> 3CH4 + 4Al(OH)3}\]

What volume of methane is obtained from 12 g of aluminium carbide?

Answer 1

\[\ce{Al4C3 + 12H2O -> 4Al(OH)3 + 3CH4}\]
144 g                             3 x 22.4 L
                                        67.2 L

144 g of Al₄C₃ will produce 67.2 L of methane

∴ 12 g of Al₄C₃ will produce

= `67.2/144 xx 12`

= 5.6 L