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Question
Albinism is known to be due to an autosomal recessive mutation. The first child of a couple with normal skin pigmentation was an albino. What is the probability that their second child will also be an albino?
Options
100%
25%
50%
75%
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Solution
25%
Explanation:
Since albinism is an autosomal recessive trait, the parents must both be heterozygous carriers (e.g., Aa) to have a child who is albino (aa). The cross between two carriers (Aa × Aa) yields a 25% chance of an albino offspring (aa), as the inheritance of each child is an independent event.
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Match list I with list II.
| List I | List II | ||
| A. | A pair of chromosomes extra with diploid | i) | monosomy |
| B. | One chromosome extra to the diploid | ii) | tetrasomy |
| C. | One chromosome loses from diploid | iii) | trisomy |
| D. | Two individual chromosomes lose from diploid | iv) | double monosomy |
Match List I with List II.
| List I | List II | ||
| A. | A pair of chromosomes extra with diploid | i) | monosomy |
| B. | One chromosome extra to the diploid | ii) | tetrasomy |
| C. | One chromosome loses from diploid | iii) | trisomy |
| D. | Two individual chromosomes lose from diploid | iv) | double monosomy |
Match list I with list II.
| List I | List II | ||
| A. | A pair of chromosomes extra with diploid | i) | monosomy |
| B. | One chromosome extra to the diploid | ii) | tetrasomy |
| C. | One chromosome loses from diploid | iii) | trisomy |
| D. | Two individual chromosomes lose from diploid | iv) | double monosomy |
Match list I with list II
| List I | List II | ||
| A. | A pair of chromosomes extra with diploid | i) | monosomy |
| B. | One chromosome extra to the diploid | ii) | tetrasomy |
| C. | One chromosome loses from diploid | iii) | trisomy |
| D. | Two individual chromosomes lose from diploid | iv) | double monosomy |
