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Question
According to Bohr’s theory of the hydrogen atom, calculate:
- angular momentum of the electron in the second Bohr orbit.
- radius of the third Bohr orbit.
Numerical
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Solution
1. Bohr quantization:
Ln = `(nh)/(2 pi)`
So, L2 = `(2 h)/(2 pi)`
= `h/pi`
= `(6.6 xx 10^-34)/3.14`
= 2.1 × 10−34 Js
2. rn = n2a0
r3 = 32a0
= 9a0
= 9 × 5.3 × 10−11
= 4.77 × 10−10 m
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