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ΔABC and ΔEDB are two similar triangles such that BD = 1/2 BC. If ar(ΔАВC) = 400 cm2, find the area (ΔEDB). - Mathematics

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Question

ΔABC and ΔEDB are two similar triangles such that BD = `1/2 BC`. If ar(ΔАВC) = 400 cm2, find the area (ΔEDB).

Sum
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Solution

Since △ABC ∼ △EDB, the ratio of their areas is equal to the square of the ratio of their corresponding sides.

Given,

`BD = 1/2 BC`

So, `(BD)/(BC) = 1/2`

Thus,

`(ar (ΔEDB))/(ar(ΔАВC)) = ((BD)/(BC))^2`

`(ar (ΔEDB))/400 = (1/2)^2`

`(ar (ΔEDB))/400 = 1/4`

`ar (ΔEDB) = 400 xx 1/4`

ar (ΔEDB) = 100

∴ ar (ΔEDB) = 100 cm2

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Chapter 13: Similarity - Exercise 13B [Page 287]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 13 Similarity
Exercise 13B | Q 5. | Page 287
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