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A wooden toy is in the shape of a cone mounted on a cylinder. The height of cone is 24 cm, the total height of the toy is 60 cm and the radius of the base of the cone is 10 cm. If the radius of base - Mathematics

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Question

A wooden toy is in the shape of a cone mounted on a cylinder. The height of cone is 24 cm, the total height of the toy is 60 cm and the radius of the base of the cone is 10 cm. If the radius of base of the cylinder is half of the radius of the base of the cone, find the total surface area of the toy. (Use π = 3.14).

Sum
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Solution

Height of the cone = 24 cm

Height of the cylinder = h2​ = 60 − 24 = 36 cm

Radius of the cone = twice the radius of the cylinder = 10 cm

Total height of toy = 60 cm

Step 1: Find slant height of cone

Slant height of the cone = `sqrt(r^2 + h^2)` 

= `sqrt(10^2 + 24^2)` 

= `sqrt(100 + 576)` 

= `sqrt(676)` 

= 26 cm 

Step 2: Curved surface area of a cone

`CSA_"cone​" = πRl`

= 3.14 × 10 × 26

= 816.4 cm2

Step 3: Curved surface area of a cylinder

`CSA_"cyl" ​=2πrh_2`

= 2 × 3.14 × 5 × 36

= 1130.4 cm2

Step 4: Exposed plane area (= πR2)     ...[= ring under cone + bottom of cylinder together]

πr2 = 3.14 × 102

= 3.14 × 100 = 314 cm2

Step 5: Total surface area

TSA = 816.4 + 1130.4 + 314

= 2260.8 cm2

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Chapter 17: Mensuration - Exercise 17D [Page 399]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 17 Mensuration
Exercise 17D | Q 14. | Page 399
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