Advertisements
Advertisements
Question
A water pump raises 50 kg of water through a height of 25 m in 5s. Calculate the power supplied by the pump (Take: g = 10 N kg−1).
Advertisements
Solution
Given m = 50 kg, g = 10N kg−1, d = 25 m, t = 5s.
Force of gravity F = mg
= 50 × 10
= 500 N
Work done W = F × d
= 500 × 25
= 12,500 J
Power P =`"W"/"t" = (12,500)/5=2500"W".`
RELATED QUESTIONS
In which of the following cases is work being done:
- A boy pushing a heavy rock
- A boy climbing up the stairs
- A coolie standing with a box on his head
- A girl moving on the road.
The moon is revolving around the earth in a circular path. How much work is done by the moon?
A water pump raises 50 litres of water through a height of 25 m in 5 s. Calculate the power of the pump required.
(Take g = 10 N kg-1 and density of water = 1000 kg m-3)
In case of negative work, the angle between the force and displacement is :
Name the CGS unit of work.
Fill in the boxe to show the corresponding energy transformation.

Why is less effort needed to lift a load over an inclined plane as compared to lifting the load directly?
A proton is kept at rest. A positively charged particle is released from rest at a distance d in its field. Consider two experiments; one in which the charged particle is also a proton and in another, a positron. In the same time t, the work done on the two moving charged particles is ______.
