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A Wall of Length 10 M Was to Be Built Across an Open Ground. the Height of the Wall is 4 M and Thickness of the Wall is 24 Cm.

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Question

A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm × 12 cm × 8 cm, How many bricks would be required?

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Solution

Given that
The wall with all its bricks makes up the space occupied by it we need to find the volume of the wall, which is nothing but cuboid.
Here, length= 10m = 1000cm
Thickness=24cm
∴The volume of the wall
= length × breadth × height
`1000xx24xx400cm^3`

Now, each brick is a cuboid with length = 24cm,
Breadth= 12cm and height= 8cm.
So, volume of each brick = length x breadth x height
`=24xx12xx8cm^3`

So, number of bricks required=`"Volume of the wall"/"Volume of each brick"`

`=(1000xx24xx400)/(24xx12xx8)`
`=4166.6`
`"So, the wall requires 167 bricks".
`

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Chapter 18: Surface Areas and Volume of a Cuboid and Cube - Exercise 18.2 [Page 31]

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R.D. Sharma Mathematics [English] Class 9
Chapter 18 Surface Areas and Volume of a Cuboid and Cube
Exercise 18.2 | Q 19 | Page 31

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