Advertisements
Advertisements
Question
A two digit number is such that the product of its digit is 14. When 45 is added to the number, then the digit interchange their places. Find the number.
Advertisements
Solution
Let the ten's digit be x, then unit's digit = `(14/x)`
Then, the number is `(10x +14/x)`
Where 45 is added to the number, the digits get interchanged.
∴ `10x + (14)/x + 45 = 10 xx (14)/x + x`
⇒ x2 + 5x - 14 = 0
⇒ (x + 7) (x + 2) = 0
⇒ x = 2
and x = -7 (inadmissible)
Hence, the number is `(10x + 14/x)`
= `(10 xx 2 + 14/2)`
= 27.
RELATED QUESTIONS
Solve the equation:`14/(x+3)-1=5/(x+1); xne-3,-1` , for x
The product of two successive integral multiples of 5 is 300. Determine the multiples.
Solve the following quadratic equation by factorisation.
\[6x - \frac{2}{x} = 1\]
Solve the following quadratic equation by factorisation.
7m2 = 21m
If 2 is a root of the equation x2 + bx + 12 = 0 and the equation x2 + bx + q = 0 has equal roots, then q =
Solve the following quadratic equation by factorization method : `"x"^2 - 5"x" - 36 = 0`
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
Find two consecutive odd integers such that the sum of their squares is 394.
2x articles cost Rs. (5x + 54) and (x + 2) similar articles cost Rs. (10x – 4), find x.
Using quadratic formula find the value of x.
p2x2 + (p2 – q2)x – q2 = 0
