Question

A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45°. Then the height (in meters) of the tower is

Options

• A. `25sqrt2`

• B. `25sqrt3`

• C. 25

• D. 12.5

Answer 1

Let AB be the tower and C be the point on the ground 25 m away from the foot of the

tower such that ∠ACB = 45°.

In right ΔABC:

`tan 45 ^@=(AB)/(BC)`

`rArr l=(AB)/25m`

⇒ AB = 25 m

Thus, the height of the tower is 25 m.

The correct answer is C.