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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 7

A strip of 4 cm wide is cut and removed from all the sides of the rectangular cardboard with dimensions 30 cm × 20 cm. Find the area of the removed portion and area of the remaining cardboard - Mathematics

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Question

A strip of 4 cm wide is cut and removed from all the sides of the rectangular cardboard with dimensions 30 cm × 20 cm. Find the area of the removed portion and area of the remaining cardboard

Sum
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Solution

Area of the outer rectangular cardboard

= L × B sq.units

= 30 × 20 cm2 

= 600 cm2

Width of the stip = 4 cm

Length of the inner rectangle = L – 2W

l = 30 – 2(4)

= 30 – 8

l = 22 cm

Breadth of the inner rectangle B = 2W

= 20 – 2(4)

= 20 – 8

b = 12 cm

Area of the inner rectangle = l × b sq.units

= 22 × 12 cm2 

= 264 cm2

Area of the remaining cardboard = 264 cm2

Area of the removed portion = Area of outer rectangle – Area of the inner rectangle

= 600 – 264 cm2

Area of the removed portion = 336 cm2

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Chapter 2: Measurements - Exercise 2.4 [Page 40]

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Samacheer Kalvi Mathematics - Term 2 [English] Class 7 TN Board
Chapter 2 Measurements
Exercise 2.4 | Q 11 | Page 40
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