Question

A stone of mass m tied to a string of length `l` is rotating along a circular path If the torque on the stone is zero, then ____________.

Options

• angular acceleration is constant

• angular acceleration is constant

• linear velocity is zero

• linear acceleration is constant

Answer 1

A stone of mass m tied to a string of length `l` is rotating along a circular path If the torque on the stone is zero, then angular acceleration is constant.

Explanation:

`tau = "I"  alpha`

`"i.e.,"  tau = "I" ("d"omega)/"dt"`

`"As"  tau = 0 Rightarrow ("d"omega)/"dt" = 0`

`therefore "m" ne 0 Rightarrow "I" ne 0`

`therefore omega = "constant"`