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Question
A square plate is contracting at the uniform rate of 3cm2/sec. The rate at which the perimeter is decreasing when the side of the square is 12 cm long is
Options
`1/2`cm/sec
`1/3`cm/sec
`1/4`cm/sec
none of these
MCQ
Derivation
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Solution
`1/2`cm/sec
Explanation:
Let A, P and x be the area, perimeter and length of the side of the square respectively at time t seconds. Then, A = x2 and P = 4x
∴ P = `4sqrt"A"`
∴ `"dP"/"dt" = 4 * 1/(2sqrt"A") * "dA"/"dt"`
`= 2/x * "dA"/"dt" = 2/12 * 3 = 1/2` cm/sec
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Derivative as a Rate Measure
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