English

A Speaks Truth in 75% Cases and B Speaks Truth in 80% Cases. Probability that They Contradict Each Other in a Statement, is (A)7 20 (B) 13 20 (C) 3 5 (D) 2 5 - Mathematics

Advertisements
Advertisements

Question

A speaks truth in 75% cases and B speaks truth in 80% cases. Probability that they contradict each other in a statement, is

Options

  •  \[\frac{7}{20}\]

  • \[\frac{13}{20}\]

  • \[\frac{3}{5}\]

  • \[\frac{2}{5}\]

MCQ
Sum
Advertisements

Solution

\[\frac{7}{20}\]
\[P\left( \text{ A speaks truth } \right) = 0 . 75\]
\[P\left( \text{ A lies } \right) = 1 - 0 . 75 = 0 . 25\]
\[P\left( \text{ B speaks truth } \right) = 0 . 8\]
\[P\left( \text{ B lies } \right) = 1 - 0 . 8 = 0 . 2\]
\[P\left( \text{ contradicting each other in a statement } \right) = P(A \text{ speaks truth and B lies } )+P\left( B\text{  speaks truth and A lies } \right)\]
\[ = 0 . 75 \times 0 . 2 + 0 . 8 \times 0 . 25\]
\[ = 0 . 15 + 0 . 2\]
\[ = 0 . 35\]
\[ = \frac{35}{100} = \frac{7}{20}\]

shaalaa.com
Problems based on Probability
  Is there an error in this question or solution?
Chapter 31: Probability - MCQ [Page 104]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 31 Probability
MCQ | Q 9 | Page 104
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×