Question

A solution of CUSO₄ is electrolyzed using a current of 1.5 amperes for 10 minutes. What mass of Cu is deposited at cathode? (At. Mass of Cu- 63.7)

Options

• 0.150 g

• 0.395 g

• 0.637 g

• 0.297 g

Answer 1

0.297 g

Explanation:

The half reaction at cathode is

\[\ce{Cu^{2+}_{(aq)} + 2e^- -> Cu_{(s)}}\]

Mole ratio = `1/2`, t = 10 min = 600 s

Mass of Cu deposited = `("I" xx "t")/96500 xx "mole ratio" xx "molar mass of Cu"`

`= (1.5 xx 600)/96500 xx 1/2 xx 63.7`

= 0.297 g