Advertisements
Advertisements
Question
A solid of mass 50 g at 150 °C is placed in 100 g of water at 11 °C when the final temperature recorded is 20 °C. Find the specific heat capacity of the solid. (specific heat capacity of water = 4.2 J/g °C)
Advertisements
Solution
Mass of the solid, ms = 50 g
Initial temperature of the solid, ts = 150C
Mass of water, mw = 100 g
Temperature of water, tw = 11°C
Final temperature of the mixture, t = 20°C
According to the principle of calorimetry
Heat gained by water = Heat lost by the solid
`:.m_wc_w(t - t_w) = m_sc_s(t_s - t)`
∴ 100 x 4.2 x (20 - 10) = 50 x cs x (150 - 20)
3780 = 6500cs
`:. c_s = 3780/6500 = 0.581` J/g °C
APPEARS IN
RELATED QUESTIONS
Give a mathematical relation between Heat Capacity and Specific Heat Capacity.
Differentiate between heat capacity and specific heat capacity.
How does green house effect help in keeping the temperature of earth’s surface suitable for living of human beings?
If 10125 J of heat energy boils off 4.5 g of water at 100°C to steam at 100°C, find the specific latent heat of steam.
Does the specific heat capacity of a substance depend upon its mass and rise in temperature only?
How much heat energy is released when 5 g of water at 20° C changes to ice at 0° C?
[Specific heat capacity of water = 4.2 J g-1 ° C-1 Specific latent heat of fusion of ice = 336 J g-1]
A. hot solid of mass 60 g at 100°C is placed in 150 g of water at 20° C. The final steady temperature recorded is 25°C. Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 J kg-1 °C-1]
Specific heat capacity of a substance X is 1900 Jkg-1°C-1 means ______.
A 0.2 kg metal at 150°C is placed in a copper calorimeter (water equivalent 0.025 kg) with 150 cm³ water at 27°C. Final temperature is 40°C. Find the specific heat of the metal.
