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Question
A solid of mass 50 g at 150 °C is placed in 100 g of water at 11 °C when the final temperature recorded is 20 °C. Find the specific heat capacity of the solid. (specific heat capacity of water = 4.2 J/g °C)
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Solution
Mass of the solid, ms = 50 g
Initial temperature of the solid, ts = 150C
Mass of water, mw = 100 g
Temperature of water, tw = 11°C
Final temperature of the mixture, t = 20°C
According to the principle of calorimetry
Heat gained by water = Heat lost by the solid
`:.m_wc_w(t - t_w) = m_sc_s(t_s - t)`
∴ 100 x 4.2 x (20 - 10) = 50 x cs x (150 - 20)
3780 = 6500cs
`:. c_s = 3780/6500 = 0.581` J/g °C
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