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Question
A sample of 1000 students whose mean weight is 119 lbs (pounds) from a school in Tamil Nadu State was taken and their average weight was found to be 120 lbs with a standard deviation of 30 lbs. Calculate the standard error of the mean
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Solution
Given n = 1000
`bar(x)` = 119 lbs ......(pounds)
Since σ is unknown
So we consider `barsigma` = s and µ = 120 lbs
S.E = `barsigma/sqrt("n")`
= `"s"/sqrt("n")`
= `30/sqrt(1000)`
= `30/31.623`
= 0.9487
Therefore the standard error for the average weight of large group of students of 120 lbs is 0.9487
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