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Question
A rod of rest length L moves at a relativistic speed. Let L' = L/γ. Its length
(a) must be equal to L'
(b) may be equal to L
(c) may be more than L' but less than L
(d) may be more than L
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Solution
(b) may be equal to L
(c) may be more than L' but less than L
If a rod of rest length L is moving at a relativistic speed v and its length is contracted to L', then
\[L' = \frac{L}{\gamma} = L\sqrt{1 - \frac{v^2}{c^2}}\]
If \[\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}},\text{ then }v < < c, \gamma \cong 1 . \]
\[ \Rightarrow L' \cong L\]
But the length of the rod may be more than L' depending on the frame of the observer. However, it cannot be more than L because as the speed of the rod increases, its length contracts more and more due to increasing value of `gamma.`
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