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Question
A reaction that is first order with respect to reactant A has a rate constant of 6 min−1. If we start with [A] = 50 mol L−1, when would [Al reach the value of 0.05 mol L−1?
Numerical
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Solution
Given:
First-order reaction
Rate constant: k = 6 min−1
Initial concentration: [A]0 = 50 mol L−1
Final concentration: [A] = 0.05 mol L−1
By using integrated rate law for first-order reactions
`t = 2.303/k log ([A]_0/([A]))`
= `2.303/6 log (50/0.05)`
= `2.303/6 log(1000)`
= `(2.303 xx 3)/6`
= `6.909/6`
t = 1.15 minutes
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