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Question
A rain drop of radius 0.3 mm has a terminal velocity in the air of 1 m/s. The viscosity of air is 18 x 10−5 poise. The viscous force on it is:
Options
101.74 × 10−4 dyne
101.74 × 10−5 dyne
16.95 × 10−4 dyne
16.95 × 10−5 dyne
MCQ
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Solution
101.74 × 10−4 dyne
Explanation:
F = 6πηrv
= 6 × 3.14 × (18 × 10−5) × 0.03 × 100
= 101.736 × 10−4 dyne
≈ 101.74 × 10−4 dyne
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Stoke's Law
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