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Question
A proton and an α-particle are accelerated through the same potential difference. Which one of the two has less kinetic energy? Justify your answer.
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Solution
The kinetic energy is related to accelerating potential as
K.E. = eV
∴ K.E.p = epV
And, K.E.α = eαV
`:.(K.E._p)/(K.E._alpha)=e_p/e_alpha`
Since, the charge on proton is less than that on alpha particle,
K.E.p < K.E.α for the same potential difference.
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