To keep total momentum the same, the third fragment must move right with speed 2v, since one piece has no horizontal speed and the other moves left with speed v.
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Question
A projectile breaks into 3 equal pieces at the top. One drops straight down, one moves left at speed v. What’s the horizontal speed of the third piece?
Options
v to the right
2v to the right
3v to the right
\[\frac {v}{2}\] to the right
MCQ
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Solution
2v to the right
Explanation:
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