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Tamil Nadu Board of Secondary EducationHSC Science Class 11

A polygon has 90 diagonals. Find the number of its sides? - Mathematics

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Question

A polygon has 90 diagonals. Find the number of its sides?

Sum
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Solution

Let the number sides of the polygon be n.

The number of diagonals of a polygon with n sides = `("n"("n" - 3))/2`

Given `("n"("n" - 3))/2` = 90

n2 – 3n = 180

n2 – 3n = 180

n2 – 3n – 180 = 0

n2 – 15n + 12n – 180 = 0

n(n – 15) + 12(n – 15) = 0

(n + 12)(n – 15) = 0

n + 12 = 0 or n – 15 = 0

n = – 12 or n = 15

But n = – 12 is not possible

∴ n = 15

∴ The number of sides of the polygon having 90 diagonals is 15.

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Chapter 4: Combinatorics and Mathematical Induction - Exercise 4.3 [Page 187]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 4 Combinatorics and Mathematical Induction
Exercise 4.3 | Q 25 | Page 187
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