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Question
A person needs a lens of power +3D for correcting his near vision and –3D for correcting his distant vision. Calculate the focal lengths of the lenses required to correct these defects.
Numerical
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Solution
P = `1/f`
P1 = +3D
= `1/f_1`
F1 = `1/3`m
= + 0.33 m (Convex lens)
P2 = –3D
= `1/f_2`
F2 = `-1/3`m
= –0.33 m (Concave lens)
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2019-2020 (March) Outside Delhi set 1
