Advertisements
Advertisements
Question
A person is listening to a tone of 500 Hz sitting at a distance of 450 m from the source of the sound. What is the time interval between successive compressions from the source?
Advertisements
Solution
The time interval between two successive compressions is equal to the time period of the wave. This time period is reciprocal of the frequency of the wave and is given by the relation:
`T=1/"Frequency"=1/500=0.002s`
APPEARS IN
RELATED QUESTIONS
Define time period.
What are longitudinal waves and transverse waves? Explain with the help of labelled diagrams.
What do you mean by the term frequency of a wave? State its S.I. unit.
How are the wave velocity V, frequency f and wavelength λ of a wave related? Derive the relationship.
The separation between two consecutive crests in a transverse wave is 100 m. If wave velocity is 20 m s-1, find the frequency of wave.
Match the pairs.
| Group ‘A’ | Group ‘B’ |
| (a) Flute | (1) Frequency less than 20 Hz |
| (b) Frequency | (2) Frequency more than 20000 Hz |
| (c) Sound level | (3) Vibrations in the air |
| (d) Ultrasonic sound | (4) Measured in Hz |
| (e) Infrasonic sound | (5) Decibel |
The diagram given below shows a displacement distance graph of a wave. If the velocity of wave is 160 ms-1, calculate:
- wavelength
- frequency
- amplitude.
An earthquake produces which kind of sound before the mainshock wave begins
