Question

A particle of mass ‘m’ is projected with a velocity υ = kV_e (k < 1) from the surface of the earth.

(V_e = escape velocity) 

The maximum height above the surface reached by the particle is:

Options

• `"Rk"^2/(1 - "k"^2)`

• `"R"("k"/(1 - "k"))^2`

• `"R"(("k")/(1 + "k"))^2"`

• `("R"^2"k")/(1 + "k")`

Answer 1

`"Rk"^2/(1 - "k"^2)`