Question

A particle of mass ‘m’ is projected with a velocity υ = kV_e(k < 1) from the surface of the earth.

(V_e = escape velocity) 

The maximum height above the surface reached by the particle is :

Options

• `R (K/(1 + k))^2`

• `(R^2k)/(1 + k)`

• `(Rk^2)/(1 - k^2)`

• `R (K/(1 - k))^2`

Answer 1

`(Rk^2)/(1 - k^2)`