Question

A particle of mass ‘m’ is projected with a velocity υ = kV_e (k < 1) from the surface of the earth.

(V_e = escape velocity)

The maximum height above the surface reached by the particle is ______

Options

• `("R"^2"k")/(1+"k")`

• `("Rk"^2)/(1-"k"^2)`

• `"R"(("k")/(1-"k"))^2`

• `"R"(("k")/(1+"k"))^2` 

Answer 1

`("Rk"^2)/(1-"k"^2)`