Question

A particle is moving along the circular path of radius 'r' with velocity 'v'. The magnitude of average acceleration after half revolution is ______.

Options

• `(3v^2)/(pir)`

• `(3v^2)/(2pir)`

• `(2v^2)/(pir)`

• `(v^2)/(pir)`

Answer 1

A particle is moving along the circular path of radius 'r' with velocity 'v'. The magnitude of average acceleration after half revolution is `underline((2v^2)/(pir))`.

Explanation:

Change in velocity `=vec"v"_2 - vec"v"_1=v-(-v)=2v`

Time taken = t `=(pir)/"v"`

∴ Average acceleration `=(2"v")/((pir)/"v")=(2"v"^2)/(pir)`