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Karnataka Board PUCPUC Science Class 11

A Nearsighted Person Cannot See Beyond 25 Cm. Assuming that the Separation of the Glass from the Eye is 1 Cm, Find the Power of Lens Needed to See Distant Objects.

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Question

A nearsighted person cannot see beyond 25 cm. Assuming that the separation of the glass from the eye is 1 cm, find the power of lens needed to see distant objects.

Answer in Brief
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Solution

Given:
As the person wears spectacles at a distance of 1 cm from the eyes.
Distance of the image from the glass, v = Distance of the image from the eye − Separation between the glass and the eye
v = 25 − 1 = 24 cm = 0.24 m
For the near-sighted person, u = ∞.
The lens formula is given by

`1/v -1/u = 1/f`

On substituting the values in the above formula, we get:

`1/f = 1/((-0.24))-1/∞ = -42`

Power of the lens, P = `1/f` = − 4.2 D
Thus, the power of the lens required to see distant objects is − 4.2 D.

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Optical Instruments: the Eye
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Chapter 19: Optical Instruments - Exercise [Page 432]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 19 Optical Instruments
Exercise | Q 21 | Page 432
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