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Question
A man running a racecourse notes that the sum of the distances from the two flag posts form him is always 10 m and the distance between the flag posts is 8 m. find the equation of the posts traced by the man.
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Solution
Let F1 and F2 be two points where the flag posts are fixed on the ground.
The origin O is the mid-point of F1F2.

∴ OF1 - OF2 = `1/2 F_1F_2 = 1/2 xx 8 = 4m`
Coordinates of F1 are (-4, 0) and F2 are (4, 0)
Let P (α, β) be any point on the track.
∴ PF1 + PF2 = 10
∴ `sqrt((α + 4)^2 + (β - 0)^2)` + `sqrt((α - 4)^2 + (β - 0)^2) = 10`
= `sqrt(α^2 + 16 + 8α + β^2)` = `10 - sqrt(α^2 + 16 - 8α + β^2)`
Squaring both sides, we get
α2 + β2 + 8α + 16 = 100 + α2 + β2 - Bα + 16 `-20 sqrt(α^2 + β^2 - 8α + 16)`
= 16α - 100 = `-20 sqrt(α^2 + β^2 - 8α + 16)`
Again, squaring both sides, we get
= (16α - 100)2 = (`-20 sqrt((α^2 + β^2 - 8α + 16)^2)`
= 256α2 + 10000 - 3200α = 400(α2 + β2 - 8α+ 16)
= 256α2 + 10000 - 3200α = 400α2 + 400β2 - 32008α+ 6400)
= 144α2 + 400β2 = 3600
= `(144α^2)/(3600) + (400β^2)/(3600) = 1`
Thus, the required equation of locus of point P is `x^2/25 + y^2/9 = 1`.
