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A man has some hens and cows. If the number of heads be 48 and number of feet by 140, how many cows are there?

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Question

A man has some hens and cows. If the number of heads be 48 and number of feet by 140, how many cows are there?

Numerical
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Solution

Let the number of hens and cow be x and y respectively.

As per the question

x + y = 48   ...(i)

2x + 4y = 140

x + 2y = 70   ...(ii)

Subtracting (i) from (ii), we have

y = 22

Hence, the number of cows is 22.

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Chapter 3: Linear Equations in Two Variables - EXERCISE 3F [Page 162]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 3 Linear Equations in Two Variables
EXERCISE 3F | Q 12. | Page 162
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