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A Man Borrows Rs 62500 at 8% P.A., Simple Interest for 2 Years. He Immediately Lends the Money Out at Ci at the Same Rate and for Same Time. What is His Gain at the End of 2 Years? - Mathematics

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Question

A man borrows Rs 62500 at 8% p.a., simple interest for 2 years. He immediately lends the money out at CI at the same rate and for same time. What is his gain at the end of 2 years?

Sum
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Solution

Case I :
Simple interest = `(62500 xx 8 xx 2)/(100)`
= 10000
Amount 
= Rs.62500 + Rs.10000
= Rs.72500
Case II :
Here P1 = Rs.62500 and r = 8%
So, Amount after 1 year
= `"P"(1 + "r"/100)`

= `62500(1 + 8/100)`

= `62500 xx (108)/(100)`
= 67500
Thus, P2 = Rs.67500 and r = 8%
Amount after 2 year
= `"P"(1 + "r"/100)`

= `67500(1 + 8/100)`

= `67500 xx (108)/(100)`
= 72900
Hence, Amount = Rs.72900
Thus, gain in amount
= Rs.72900 - Rs.72500
= Rs.400.

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Chapter 3: Compound Interest - Exercise 3.1

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Frank Mathematics [English] Class 9 ICSE
Chapter 3 Compound Interest
Exercise 3.1 | Q 17

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