English
Karnataka Board PUCPUC Science 2nd PUC Class 12

A long straight wire carries a current of 35 A. What is the magnitude of the field B at a point 20 cm from the wire?

Advertisements
Advertisements

Question

A long straight wire carries a current of 35 A. What is the magnitude of the field B at a point 20 cm from the wire?

Numerical
Advertisements

Solution

Given: Current in the wire, I = 35 A

Distance of a point from the wire, r = 20 cm = 0.2 m

Formula: The magnitude of the magnetic field at this point is given as:

B = `(mu_0I)/(2pix)`

= `(4pi xx 10^-7 xx 35)/(2 xx pi xx 0.2)`

= `35xx10^-7/0.1    ...[∵ 0.1xx10/10 = 1/10 = 10^-1]`

= 35 × 10–6 T

= 3.5 × 10–5 T

Hence, the magnitude of the magnetic field at a point 20 cm from the wire is 3.5 × 10–5 T.

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Moving Charges and Magnetism - EXERCISES [Page 134]

APPEARS IN

NCERT Physics Part I and II [English] Class 12
Chapter 4 Moving Charges and Magnetism
EXERCISES | Q 4.2 | Page 134
NCERT Physics Part I and II [English] Class 12
Chapter 4 Moving Charges and Magnetism
Exercise | Q 4.2 | Page 169
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×