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Question
A light ray passes from a vacuum into a medium of refractive index n. The angle of refraction is found to be half the angle of incidence. The angle of incidence is ______.
Options
`cos^-1 (n/2)`
`2cos^-1 (n/2)`
2 sin−1 (n)
`2sin^-1 (n/2)`
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Solution
A light ray passes from a vacuum into a medium of refractive index n. The angle of refraction is found to be half the angle of incidence. The angle of incidence is `bbunderline(2cos^-1 (n/2))`.
Explanation:
Given: Light is passing from a vacuum to a medium of refractive index n.
Angle of refraction, r = `i/2`
Apply Snell’s law:
sin i = `n sin(i/2)`
Use identity:
sin i = `2 sin(i/2) cos(i/2)`
Substitute:
`2 sin(i/2) cos(i/2) = n sin(i/2)`
Cancel `sin(i/2)` from both sides:
⇒ `2 cos(i/2) = n`
⇒ `cos(i/2) = n/2`
⇒ `cos^-1(n/2)`
⇒ i = `2 cos^-1(n/2)`
