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A ladder 25 m long reaches a window at a height of 7 m above the ground. Keeping its foot at the same point, the ladder is turned so that it reaches a window 20 m high across the street. - Mathematics

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Question

A ladder 25 m long reaches a window at a height of 7 m above the ground. Keeping its foot at the same point, the ladder is turned so that it reaches a window 20 m high across the street. Find the total width of the street.

Sum
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Solution

Given,


In △ADC

⇒ AD2 + AC2 = CD2

⇒ 72 + AC2 = 252

⇒ AC2 = 625 – 49

⇒ AC2 = 576

⇒ AC = `sqrt(576)` = 24 m

In △BEC,

EC2 = BC2 + BE2

⇒ 252 = BC2 + 202

⇒ BC2 = 625 – 400 = 225

⇒ BC = `sqrt(225)` = 15 m

Now the total width of the street is 24 m + 15 m = 39 m

Hence, this is the required.

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Chapter 11: Pythagoras Theorem - EXERCISE 11 [Page 126]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 11 Pythagoras Theorem
EXERCISE 11 | Q 21. | Page 126
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