Advertisements
Advertisements
Question
A Kabaddi coach has 14 players ready to play. How many different teams of 7 players could the coach put on the court?
Advertisements
Solution
Number of kabaddi players = 14
7 players must be selected from 14 players
Number of ways of selecting 7 players from 14 players is
= 14C7
= `(14!)/(7!(14 - 7)!)`
= `(14!)/(7!7!)`
= `(14 xx 13 xx 12 xx 1 xx 10 xx 9 xx 8 xx 7!)/(7! xx 7 xx 6xx 5 xx 4 xx 3 xx 2 xx 1)`
= `(14 xx 13 xx 12 xx11 xx 10 xx 9 xx 8)/(7 xx 6 xx 5 xx 4 xx 3 xx 2 xx 1)`
= 13 × 11 × 4 × 3 × 2
= 3432
APPEARS IN
RELATED QUESTIONS
If nPr = 1680 and nCr = 70, find n and r.
How many triangles can be formed by joining the vertices of a hexagon?
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
If a polygon has 44 diagonals, find the number of its sides.
In how many different ways, 2 Mathematics, 2 Economics and 2 History books can be selected from 9 Mathematics, 8 Economics and 7 History books?
If nC3 = nC2 then the value of nC4 is:
The number of 3 letter words that can be formed from the letters of the word ‘NUMBER’ when the repetition is allowed are:
There are 10 true or false questions in an examination. Then these questions can be answered in
If nPr = 720 and nCr = 120, find n, r
There are 5 teachers and 20 students. Out of them a committee of 2 teachers and 3 students is to be formed. Find the number of ways in which this can be done. Further find in how many of these committees a particular student is excluded?
In an examination a student has to answer 5 questions, out of 9 questions in which 2 are compulsory. In how many ways a student can answer the questions?
A committee of 7 peoples has to be formed from 8 men and 4 women. In how many ways can this be done when the committee consists of at most 3 women?
Find the number of strings of 4 letters that can be formed with the letters of the word EXAMINATION?
How many triangles can be formed by joining 15 points on the plane, in which no line joining any three points?
There are 11 points in a plane. No three of these lies in the same straight line except 4 points, which are collinear. Find, the number of straight lines that can be obtained from the pairs of these points?
Choose the correct alternative:
The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of three parallel lines
Choose the correct alternative:
In a plane there are 10 points are there out of which 4 points are collinear, then the number of triangles formed is
Choose the correct alternative:
The number of ways of choosing 5 cards out of a deck of 52 cards which include at least one king is
Choose the correct alternative:
The product of first n odd natural numbers equals
Choose the correct alternative:
If nC4, nC5, nC6 are in AP the value of n can be
