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Question
A galvanometer of resistance 25 `Omega` is shunted by 2.5 `Omega` resistance. The part (fraction) of the total current that flows through the galvanometer is given as ______.
Options
`"I"_"G"/"I"_"0"= 1/11`
`"I"_"G"/"I"_"0"= 2/11`
`"I"_"G"/"I"_"0"= 3/11`
`"I"_"G"/"I"_"0"= 4/11`
MCQ
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Solution
A galvanometer of resistance 25 `Omega` is shunted by 2.5 `Omega` resistance. The part (fraction) of the total current that flows through the galvanometer is given as `"I"_" G"/"I"_"0" = 1/11`.
Explanation:
`"I"_" G"/"I" = "S"/"S" + "G"`
`2.5/(2.5 + 2.5`
`"I"_" G"/"I" = 2.5/27.5 = 25/275 = 1/11`
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